Multiples in the Fibonacci Series
I found the following problem on K. Rustan M. Leino’s puzzles page:
[Carroll Morgan told me this puzzle.]
Prove that for any positive K, every Kth number in the Fibonacci sequence is a multiple of the Kth number in the Fibonacci sequence.
More formally, for any natural number n, let F(n) denote Fibonacci number n. That is, F(0) = 0, F(1) = 1, and F(n+2) = F(n+1) + F(n). Prove that for any positive K and natural n, F(n*K) is a multiple of F(K).
This problem caught my attention, because it looks like a good example for using a result that I have derived last year. My result gives a reasonable sufficient condition for showing that a function distributes over the greatest common divisor and shows that the Fibonacci function satisfies the condition.
The crucial step is clearly the one where we apply the distributivity property.
Distributivity properties are very important, because they allow us to rewrite
expressions in a way that prioritizes the function that has the most relevant
properties. In the example above we could not simplify
(Now that I think about it, perhaps it would be a good idea to write a note on distributivity properties, summarizing their importance and their relation with symbol dynamics.)
If you have any corrections, questions, or alternative proofs, please get in touch!